The acceleration due to gravity on moon is 1/6 th of that on the earth. If the length of the seconds pendulum is 96 m on the earth, what is its length on the moon?

Explanation

For seconds pendulum, time period is 2s
`T=2pisqrt(l/g)` for simple pendulum
time remains constnat in both the planets
`l/g="constant" " " :. (l_(m))/(g_(m))=(l_(e))/(g_(e))` (or) `(l_(m))/(((g_(e))/6))=96/(g_(e))`