A force F = 2.0 N acts on a particle P in the xz-plane. The force F is parallel to x-axis. The particle P (as shown in the figure) is at a distance 3 m and the line joining P with the origin makes angle `30^(@)` with the x-axis. The magnitude of torque on P with respect to origin O (in N m) is

Options

A. 2
B. 3
C. 4
D. 5

Answer

B

Explanation

Torque , `vectau = vecr xx vecF`
In magnitude , `tau = r F sin theta`where `theta` is the angle between `vecr` and `vecF`
Here F = 2 . 0 N , r= 3 m , `theta = 30^(@)`
`therefore` The magnitude of torque on P with respect to origin O is
`tau = (3 m) (2 , 0 N) sin 30^(@) = (3m) (2.0N) ((1)/(2)) = 3 Nm`