A uniform horizontal metre scale of mass m is suspended by two vertical strings attached to its two ends. A body of mass 2m is placed on the 75 cm mark. The tensions in the two strings are in the ratio is

Options

A. `1: 2`
B. `1 : 3`
C. `2 : 3`
D. `3 : 4`

Answer

A

Explanation

`T_(1) + T_(2) = 3mg`
Taking torques about A , we get 0.5 mg + 0.75 `xx 2 mg = 1 xx T_(1) therefore T_(2) = 2 mg`
Similarly , taking torque about B , we get `T_(1) = mg`
`therefore (T_(1))/(T_(2)) = (1)/(2)`