The moment of inertia of a thin uniform rod of mass M and length l about an axis perpendicular to the rod through its centre is I. The moment of inertia of the rod through its end point is

Options

A. `(I)/(4)`
B. `(I)/(2)`
C. `2I`
D. `4I`

Answer

D

Explanation

The moment of inertia of a thin uniform rod of mass M and length l about an axis perpendicular to the rod through its centre is
`l = (Ml^(2))/(12) " " … (i)`
The moment of inertia of the rod through its end point is
`I. = (Ml^2)/(3) = 4 ((Ml^2)/(12)) = 4l " "` (Using (i))