A solid cylinder of mass 20 kg has length 1 m and radius 0.2 m. Then its moment of inertia (in kg m ) about its geometrical axis is (in kg `m^2`)

Options

A. 0.8
B. 0.4
C. 0.2
D. 0.6

Answer

B

Explanation

The moment of inertia of cylinder about the geometrical axis = `(MR^(2))/(2) = (20 xx (0.2)^(2))/(2) = 0.4kg m^(2)`