The radius of gyration of a solid cylinder of mass M and radius R about its own axis is

Options

A. `(R)/(sqrt2)`
B. `(R)/(2)`
C. `(R)/(sqrt3)`
D. `(R)/(3)`

Answer

A

Explanation

The moment of inertia of a solid cylinder of mass M and radius R about its own axis is
`I = (MR^(2))/(2) " " … (i)`
As `I = Mk^(2)` (where k is the radius or gyration) `" "` … (ii)
From (i) and (ii) , we get
`k^(2) = (R^(2))/(2) or k = (R)/(sqrt2)`