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Moment of inertia of a ring of mass M an...

Moment of inertia of a ring of mass M and radius R about an axis passing through the centre and perpendicular to the plane is I. What is the moment of inertia about its diameter?

A

I

B

`(I)/(2)`

C

`(I)/(sqrt2)`

D

`I + MR^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Moment of inertia of the ring of mass M and radius R about an axis passing through the centre and perpendicular to the plane ,
`I = MR^(2) " " … (i)`
Moment of inertia of the ring about its diameter
`I_("diameter") = (MR^(2))/(2) = (1)/(2) (MR^(2)) = (I)/(2) " "` (Using (i))
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