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Moment of inertia of a uniform rod of le...

Moment of inertia of a uniform rod of length L and mass M , about an axis pasing through L/4 from one end and perpendicular to its length is

A

`(7)/(36) ML^2`

B

`(7)/(48) ML^2`

C

`(11)/(48) ML^2`

D

`(ML^2)/(12)`

Text Solution

Verified by Experts

The correct Answer is:
B

Applying theorem of parallel axes ,
`I = I_(0) + M((L)/(4))^(2) = (ML^2)/(12) + (ML^2)/(16) = (7)/(48) ML^2`
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