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A hoop of mass M and radius R is hung fr...

A hoop of mass M and radius R is hung from a support fixed in a wall . Its moment of inertia about the support is

A

`2MR^2`

B

`3 M R^2`

C

`4 M R^2`

D

`6 M R^2`

Text Solution

Verified by Experts

The correct Answer is:
A

A hoop is a circular ring `therefore I_(0) = MR^(2)`
By theorem of parallel axes ,
`I = I_(0) + MR^(2) = MR^(2) + MR^(2) = 2 MR^(2)`
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