The moment of inertia of a circular ring about one of its diameters is I . What will be its moment of inertia about a tangent parallel to the diameter?

Options

A. 4 I
B. 2 I
C. `(3)/(2) I`
D. `3 I`

Answer

D

Explanation

`I = (1)/(2) MR^(2) " "… (i)`
According to theorem of parallel axes , the moment of inertia about the given axis is
`I. = (1)/(2) MR^(2) + MR^(2) = (3)/(2) MR^(2) = 3I " "` (Using (i))