A sphere of mass 10 kg and radius 0.5 m rotates about a tangent. The moment of inertia of the sphere is

Options

A. 5 kg `m^(2)`
B. `2.7` kg `m^(2)`
C. 3.5 kg `m^(2)`
D. 4.5 kg `m^(2)`

Answer

C

Explanation

Moment of inertia about tangent = `I + MR^(2) = (2)/(5) MR^(2) + MR^(2) = (7)/(5) MR^(2) = (7)/(5) xx (10) xx (0.5)^(2) = 3.5 kg m^(2)`