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A mass is whirled in a circular path wit...

A mass is whirled in a circular path with constant angular velocity and its angular momentum is L. If the string is now halved keeping the angular velocity the same, the angular momentum is

A

`(L)/(4)`

B

`(L)/(2)`

C

L

D

2 L

Text Solution

Verified by Experts

The correct Answer is:
A
L = `mr^(2) omega` . For given m and `omega , L prop r^(2)` . If r is halved , the angular momentum L becomes one -fourth .
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