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Consider a body shown in figure consisting two identical balls, cach of mass M connected by a light rigid rod. If an impulse J - Mv is imparted to the body at one of its ends, what would be its angular velocity ?

A

`(v)/(L)`

B

`(2v)/(L)`

C

`(v)/(3L)`

D

`(v)/(4L)`

Text Solution

Verified by Experts

The correct Answer is:
A


Let `omega` be the angular velocity of the rod about the centre of mass C .
As angular impulse = change in angular momentum about the centre of mass of the system
`therefore J ""(L)/(2) = I_(C) omega or M_(v) ((L)/(2)) = 2 ((ML^(2))/(4)) omega or omega = (v)/(L)`
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