A body of mass 1.0 kg is rotating on a circular path of diameter 2.0 m at the rate of 10 rotations in 31.4 s. The angular momentum of the body, in kg `m^2`/s, is

Options

A. `1.0`
B. `1.5`
C. `2.0`
D. `4.0`

Answer

C

Explanation

Here , Mass M = 1.0 kg , Diameter , D = 2.0 m
`therefore` Radius `R = (D)/(2) = 1.0` m
The moment of inertia of the body is `I = MR^(2) = (1.0 Kg) (1.0 m)^(2) = 1.0 kg m^(2)`
The angular velocity of the body is
`omega = 2 pi epsilon = 2 xx 3.14 xx (10)/(31.4)` = rad/s = 2 rad/s
The angular momentum of the body is `L = I omega = (1.0 kg m^(2))` (2 rad/s) = 2 kg `m^(2)//s`