Figure shows the position-time graph of a particle of mass 4kg. Let the force on the particle for `tlt0` , `0ltt`lt,`4s` , `tgt4s` be `F_(1) , F_(2)` and `F_(3)` respectively. Then

Options

A. `F_(1)=F_(2)=F_(3)=0`
B. `F_(1)gtF_(2)=F_(3)`
C. `F_(1)gtF_(2)gtF_(3)`
D. `F_(1)ltF_(2)ltF_(3)`

Answer

A

Explanation

For `t lt 0 and t ge 4s`, the position of the particle is not changing i.e. the particle is at rest. So no force is acting on the particle at these intevals. For `0 lt t lt 4s`. The position of the particle is continuously changing. As the position time graph is a straight line, the motion of the particle is uniform, so acceleration, a=0, Hence no force acts on the particle during the interval also.