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In the question number 66, the tension i...

In the question number 66, the tension in the string is

A

30N

B

36N

C

34N

D

32N

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To solve the problem of finding the tension in the string, we can follow these steps: ### Step 1: Understand the System We have a block and a trolley system where the block is hanging and connected to the trolley via a string. We need to find the tension in the string. ### Step 2: Identify Given Values From the transcript, we have: - The acceleration \( a = 1.5 \, \text{m/s}^2 \) - The gravitational acceleration \( g = 10 \, \text{m/s}^2 \) - The mass of the block \( m = 4 \, \text{kg} \) (since \( 4g \) is mentioned) ### Step 3: Write the Equation of Motion For the block hanging, we can write the equation of motion as: \[ 4g - T = 4a \] Where: - \( T \) is the tension in the string. - \( 4g \) is the weight of the block. ### Step 4: Substitute Known Values Substituting the known values into the equation: \[ 4(10) - T = 4(1.5) \] This simplifies to: \[ 40 - T = 6 \] ### Step 5: Solve for Tension Now, we can solve for \( T \): \[ 40 - 6 = T \] \[ T = 34 \, \text{N} \] ### Conclusion The tension in the string is \( 34 \, \text{N} \).

To solve the problem of finding the tension in the string, we can follow these steps: ### Step 1: Understand the System We have a block and a trolley system where the block is hanging and connected to the trolley via a string. We need to find the tension in the string. ### Step 2: Identify Given Values From the transcript, we have: - The acceleration \( a = 1.5 \, \text{m/s}^2 \) ...
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