An aircraft executes a horizontal loop at a speed of `720 km h^(-1)` , with its wings banked at `15^(@)` What is the radiue of the loop ?

Options

A. 14.8km
B. 14.8m
C. 29.6km
D. 29.6m

Answer

A

Explanation

Here, `v=720 km h^(-1)=720xx(5)/(18)ms^(-1)=200 ms^(-1)`
`theta=15^(@), g=10ms^(-2) "As" tan theta=(v^(2))/(rg)`
`therefore r=(v^(2))/(tan thetag)=(200 ms^(-1))^(2)/(tan 15^(@)xx10ms^(-2))=14815m=14.8km`