Two masses of 5 kg and 3 kg are suspended with the help of massless inextensible strings as shown in figure. The whole system is going upwards with an acceleration of `2m s^(-2)`. The tensions `T_(1) and T(2)` are respectively `("Take g"=10ms^(-2))`

Options

A. 96N, 36N
B. 36N,96N
C. 96N,96N
D. 36N,36N

Answer

A

Explanation

The free body diagram of (3) kg block is as shown in the Fig. (a) The equation of motion of 3 kg block is `T_(2)=3g=3a`
`T_(2)=3(a+g)=3(2+10)=36...(i)`

The equation of motion of 5 kg block is `T_(1)-T_(2)-5g=5a`
The equation of motion of 6 kg block is `T_(1)-T_(2)-5g=5a`
`T_(1)=5(a+g)+T_(2) =5(2+10)+36=96N`