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Let Y(s) and Y(A) represent Young's mod...

Let `Y_(s)` and `Y_(A)` represent Young's modulus for steel and aluminium respectively. It is said that steel is more elastic than aluminium.Therefore, it follows that

A

`Y_(s) =Y_(A)`

B

`Y_(s) lt Y_(A)`

C

`Y_(s) gt Y_(A)`

D

`(Y_(S))/(Y_(A)) = 0`

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The correct Answer is:
To solve the problem, we need to analyze the relationship between Young's modulus and the elasticity of materials. Here's a step-by-step breakdown: ### Step 1: Understand Young's Modulus Young's modulus (Y) is defined as the ratio of stress to strain in a material. Mathematically, it is expressed as: \[ Y = \frac{\text{Stress}}{\text{Strain}} \] Where: - Stress \( = \frac{F}{A} \) (Force per unit area) - Strain \( = \frac{\Delta L}{L} \) (Change in length per original length) ### Step 2: Define Elasticity Elasticity refers to the ability of a material to return to its original shape after the removal of a load. A material is considered more elastic if it deforms less under the same applied stress. ### Step 3: Compare Steel and Aluminium The problem states that steel is more elastic than aluminium. This means that when the same force is applied to both materials, steel will experience less deformation (elongation) compared to aluminium. ### Step 4: Relate Elasticity to Young's Modulus Since steel is more elastic, it will have a smaller strain for the same stress compared to aluminium. Therefore, we can conclude: - If \( \Delta L_s \) is the elongation in steel and \( \Delta L_a \) is the elongation in aluminium, then: \[ \Delta L_s < \Delta L_a \] ### Step 5: Express Young's Modulus for Both Materials Using the definition of Young's modulus: - For steel: \[ Y_s = \frac{F/A}{\Delta L_s/L} \] - For aluminium: \[ Y_a = \frac{F/A}{\Delta L_a/L} \] ### Step 6: Analyze the Relationship Since \( \Delta L_s < \Delta L_a \), it follows that: \[ Y_s > Y_a \] This means that the Young's modulus for steel is greater than that for aluminium. ### Conclusion From the analysis, we conclude that: \[ Y_s > Y_a \] ### Final Answer Therefore, the correct option is: **\( Y_s > Y_a \)** ---

To solve the problem, we need to analyze the relationship between Young's modulus and the elasticity of materials. Here's a step-by-step breakdown: ### Step 1: Understand Young's Modulus Young's modulus (Y) is defined as the ratio of stress to strain in a material. Mathematically, it is expressed as: \[ Y = \frac{\text{Stress}}{\text{Strain}} \] Where: - Stress \( = \frac{F}{A} \) (Force per unit area) - Strain \( = \frac{\Delta L}{L} \) (Change in length per original length) ...
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NCERT FINGERTIPS ENGLISH-MECHANICAL PROPERTIES OF SOLIDS-ELASTIC MODULI
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  3. Let Y(s) and Y(A) represent Young's modulus for steel and aluminium ...

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  5. If the work done in stretching a wire by 1mm is 2J, then work necessar...

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  7. Four identical hollow cylindrical cloumns of steel support a big struc...

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  8. The elastic energy stored per units volume in a streched wire is

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  9. Two wires of the same material and length but diameter in the ratic 1:...

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  18. A steel wire can support a maximum load of W before reaching its elast...

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