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The density of water at the surface of o...

The density of water at the surface of ocean is `rho` . If the bulk modulus of water is `B`, then the density of ocean water at depth, when the pressure at a depth is `alphap_(0)` and `p_(0)` is the atmospheric pressure is

A

`(rhoK)/(k-nP_(0))`

B

`(rhoK)/(K +nP_(0))`

C

`(rhoK)/(K-(n-1)P_(0))`

D

`(rhoK)/((K+(n-1)P_(0)))`

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The correct Answer is:
To find the density of ocean water at a certain depth where the pressure is given, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Given Values**: - Density of water at the surface: \( \rho \) - Bulk modulus of water: \( B \) - Pressure at depth: \( \alpha P_0 \) (where \( P_0 \) is atmospheric pressure) 2. **Understand the Relationship**: - The bulk modulus \( B \) is defined as: \[ B = -V \frac{dP}{dV} \] - This means that an increase in pressure causes a decrease in volume, which in turn increases density. 3. **Relate Initial and Final States**: - Let \( V_1 \) be the initial volume and \( V_2 \) be the final volume at depth. - The initial density \( \rho_1 \) is \( \rho \) and the final density \( \rho_2 \) can be expressed as: \[ \rho_2 = \frac{\rho_1 V_1}{V_2} \] 4. **Calculate Change in Pressure**: - The change in pressure \( \Delta P \) when going from the surface to depth is: \[ \Delta P = \alpha P_0 - P_0 = (\alpha - 1) P_0 \] 5. **Express Change in Volume**: - Using the definition of bulk modulus: \[ B = V_1 \frac{(\alpha - 1) P_0}{\Delta V} \] - Rearranging gives: \[ \Delta V = V_1 \frac{(\alpha - 1) P_0}{B} \] 6. **Relate Final Volume to Initial Volume**: - The final volume \( V_2 \) can be expressed as: \[ V_2 = V_1 - \Delta V = V_1 - V_1 \frac{(\alpha - 1) P_0}{B} \] - Simplifying gives: \[ V_2 = V_1 \left(1 - \frac{(\alpha - 1) P_0}{B}\right) \] 7. **Substitute Back to Find Density**: - Now substituting \( V_2 \) back into the density equation: \[ \rho_2 = \frac{\rho V_1}{V_1 \left(1 - \frac{(\alpha - 1) P_0}{B}\right)} = \frac{\rho}{1 - \frac{(\alpha - 1) P_0}{B}} \] 8. **Final Expression**: - Therefore, the density of ocean water at depth is: \[ \rho_2 = \frac{\rho B}{B - (\alpha - 1) P_0} \]

To find the density of ocean water at a certain depth where the pressure is given, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Given Values**: - Density of water at the surface: \( \rho \) - Bulk modulus of water: \( B \) - Pressure at depth: \( \alpha P_0 \) (where \( P_0 \) is atmospheric pressure) ...
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