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The relation between Y. eta and B is...

The relation between Y. `eta` and B is

A

`(1)/(Y) = (1)/(3eta) +(1)/(9B)`

B

`(9)/(Y)=(1)/(eta) +(3)/(B)`

C

`(1)/(eta) =(1)/(B) +(1)/(Y)`

D

`(9)/(Y) = (3)/(eta) +(1)/(B)`

Text Solution

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The correct Answer is:
To find the relation between Young's modulus (Y), rigidity modulus (η), and bulk modulus (B), we can follow these steps: ### Step 1: Write down the definitions Young's modulus (Y), rigidity modulus (η), and bulk modulus (B) are defined as follows: - Young's modulus (Y) is defined as the ratio of tensile stress to tensile strain. - Rigidity modulus (η) is defined as the ratio of shear stress to shear strain. - Bulk modulus (B) is defined as the ratio of volumetric stress to the change in volume strain. ### Step 2: Use the relationships between the moduli From material mechanics, we have the following relationships: 1. \( Y = 2η(1 + u) \) (where \( u \) is Poisson's ratio) 2. \( Y = 3B(1 - 2u) \) ### Step 3: Rearrange the equations We can rearrange these equations to express them in terms of Y, η, and B. From the first equation, we can express η: \[ η = \frac{Y}{2(1 + u)} \quad \text{(Equation 1)} \] From the second equation, we can express B: \[ B = \frac{Y}{3(1 - 2u)} \quad \text{(Equation 2)} \] ### Step 4: Substitute the expressions into a single equation To find a relation involving all three moduli, we can substitute the expressions for η and B into a single equation. We can manipulate the equations as follows: 1. Substitute η from Equation 1 into the relation \( \frac{9}{Y} = \frac{3}{η} + \frac{1}{B} \): \[ \frac{9}{Y} = \frac{3(2(1 + u))}{Y} + \frac{1}{\frac{Y}{3(1 - 2u)}} \] 2. Simplifying this gives: \[ \frac{9}{Y} = \frac{6(1 + u)}{Y} + \frac{3(1 - 2u)}{Y} \] ### Step 5: Combine the terms Now, combine the terms on the right-hand side: \[ \frac{9}{Y} = \frac{6(1 + u) + 3(1 - 2u)}{Y} \] This simplifies to: \[ \frac{9}{Y} = \frac{9 - 3u}{Y} \] ### Step 6: Final relation Thus, we can conclude that: \[ \frac{9}{Y} = \frac{3}{η} + \frac{1}{B} \] ### Final Answer The relation between Young's modulus (Y), rigidity modulus (η), and bulk modulus (B) is: \[ \frac{9}{Y} = \frac{3}{η} + \frac{1}{B} \]

To find the relation between Young's modulus (Y), rigidity modulus (η), and bulk modulus (B), we can follow these steps: ### Step 1: Write down the definitions Young's modulus (Y), rigidity modulus (η), and bulk modulus (B) are defined as follows: - Young's modulus (Y) is defined as the ratio of tensile stress to tensile strain. - Rigidity modulus (η) is defined as the ratio of shear stress to shear strain. - Bulk modulus (B) is defined as the ratio of volumetric stress to the change in volume strain. ...
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