Combine three resistors `5Omega, 4.5Omega and 3Omega` is such a way that the total resistance of this combination maximum

Options

A. `12.5Omega`
B. `13.5Omega`
C. `14.5Omega`
D. `16.5Omega`

Explanation

To find the maximum total resistance when combining three resistors of values 5Ω, 4.5Ω, and 3Ω, we can follow these steps:

### Step 1: Understand the combinations
Resistors can be combined in two ways: in series and in parallel.

- **Series Combination**: The total resistance (R_total) is the sum of the individual resistances.

\[ R_{total} = R_1 + R_2 + R_3 \]

- **Parallel Combination**: The total resistance is given by the reciprocal of the sum of the reciprocals of the individual resistances.

\[ \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} \]

### Step 2: Calculate the total resistance in series
To maximize the total resistance, we will connect the resistors in series.

1. Identify the resistances:
- \( R_1 = 5Ω \)
- \( R_2 = 4.5Ω \)
- \( R_3 = 3Ω \)

2. Apply the series formula:
\[ R_{total} = R_1 + R_2 + R_3 = 5Ω + 4.5Ω + 3Ω \]

3. Calculate:
\[ R_{total} = 5 + 4.5 + 3 = 12.5Ω \]

### Step 3: Conclusion
The maximum total resistance when combining the three resistors is **12.5Ω**.

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