Three resistors of resistances `3Omega, 4Omega and 5Omega` are combined in parallel. This combination is connected to a battery of emf 12V and negligible internal resistance, current through each resistor in ampere is

Options

A. 4,3,2.4
B. 8,7,3,4
C. 2,5,1,8
D. 5,5,8,2

Explanation

To solve the problem of finding the current through each resistor in a parallel circuit, follow these steps:

### Step 1: Understand the Circuit Configuration
We have three resistors:
- R1 = 3Ω
- R2 = 4Ω
- R3 = 5Ω

These resistors are connected in parallel to a battery with an EMF of 12V.

### Step 2: Identify the Voltage Across Each Resistor
In a parallel circuit, the voltage across each resistor is the same and equal to the voltage of the battery. Therefore, the voltage (V) across each resistor is:
\[ V = 12V \]

### Step 3: Use Ohm's Law to Calculate Current
Ohm's Law states that:
\[ I = \frac{V}{R} \]
where:
- \( I \) is the current through the resistor,
- \( V \) is the voltage across the resistor,
- \( R \) is the resistance of the resistor.

### Step 4: Calculate Current Through Each Resistor
1. **For R1 (3Ω)**:
\[ I_1 = \frac{V}{R_1} = \frac{12V}{3Ω} = 4A \]

2. **For R2 (4Ω)**:
\[ I_2 = \frac{V}{R_2} = \frac{12V}{4Ω} = 3A \]

3. **For R3 (5Ω)**:
\[ I_3 = \frac{V}{R_3} = \frac{12V}{5Ω} = 2.4A \]

### Step 5: Summarize the Results
The current through each resistor is:
- \( I_1 = 4A \)
- \( I_2 = 3A \)
- \( I_3 = 2.4A \)

### Final Answer
The currents through the resistors are:
- 4 amperes through the 3Ω resistor,
- 3 amperes through the 4Ω resistor,
- 2.4 amperes through the 5Ω resistor.

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