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The work function for Al, K and Pt is 4....

The work function for Al, K and Pt is 4.28 eV, 2.30 eV and 5.65 eV respectively. Their respective threshold frequencies would be

A

`PtgtAlgtK`

B

`AlgtPtgtK`

C

`KgtAlgtPt`

D

`AlgtKgtPt`

Text Solution

AI Generated Solution

The correct Answer is:
To find the threshold frequencies for Aluminum (Al), Potassium (K), and Platinum (Pt) based on their work functions, we can use the formula that relates the work function (φ) to the threshold frequency (ν₀): \[ \phi = h \nu_0 \] Where: - φ is the work function in electron volts (eV), - h is Planck's constant (approximately \(4.135667696 \times 10^{-15} \text{ eV s}\)), - ν₀ is the threshold frequency in hertz (Hz). ### Step 1: Convert Work Function to Threshold Frequency We can rearrange the formula to solve for the threshold frequency: \[ \nu_0 = \frac{\phi}{h} \] ### Step 2: Calculate the Threshold Frequencies Now, we will calculate the threshold frequencies for each metal. 1. **For Potassium (K)**: - Work function (φ) = 2.30 eV - Threshold frequency (ν₀) = \(\frac{2.30 \text{ eV}}{4.135667696 \times 10^{-15} \text{ eV s}}\) \[ \nu_{0(K)} = \frac{2.30}{4.135667696 \times 10^{-15}} \approx 5.56 \times 10^{14} \text{ Hz} \] 2. **For Aluminum (Al)**: - Work function (φ) = 4.28 eV - Threshold frequency (ν₀) = \(\frac{4.28 \text{ eV}}{4.135667696 \times 10^{-15} \text{ eV s}}\) \[ \nu_{0(Al)} = \frac{4.28}{4.135667696 \times 10^{-15}} \approx 1.04 \times 10^{15} \text{ Hz} \] 3. **For Platinum (Pt)**: - Work function (φ) = 5.65 eV - Threshold frequency (ν₀) = \(\frac{5.65 \text{ eV}}{4.135667696 \times 10^{-15} \text{ eV s}}\) \[ \nu_{0(Pt)} = \frac{5.65}{4.135667696 \times 10^{-15}} \approx 1.37 \times 10^{15} \text{ Hz} \] ### Step 3: Order the Threshold Frequencies Now we can summarize the threshold frequencies: - ν₀(K) ≈ \(5.56 \times 10^{14} \text{ Hz}\) - ν₀(Al) ≈ \(1.04 \times 10^{15} \text{ Hz}\) - ν₀(Pt) ≈ \(1.37 \times 10^{15} \text{ Hz}\) ### Step 4: Establish the Order The order of threshold frequencies from lowest to highest is: - K < Al < Pt ### Final Answer The respective threshold frequencies in increasing order are: - K < Al < Pt

To find the threshold frequencies for Aluminum (Al), Potassium (K), and Platinum (Pt) based on their work functions, we can use the formula that relates the work function (φ) to the threshold frequency (ν₀): \[ \phi = h \nu_0 \] Where: - φ is the work function in electron volts (eV), ...
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NCERT FINGERTIPS ENGLISH-DUAL NATURE OF RADIATION AND MATTER -EINSTEIN S PHOTOELECTRIC EQUATION : ENERGY QUANTUM OF RADIATION
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  2. Light of wavelength 0.6 mum from a sodium lamp falls on a photocell an...

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  5. Photoelectric emission occurs only when the incident light has more th...

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  7. The photoelectric threshold wavelength for silver is lamda(0). The ene...

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  8. A photon of energy E ejects a photoelectron from a metel surface whose...

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  9. Two identical photocathodes receive light of frequencies v(1) and v(2)...

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  10. A metallic surface is irradiated by a monochromatic light of frequency...

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  17. A light of wavelength 600 nm is incident on a metal surface. When ligh...

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  18. The threshold frequency of a certain metal is 3.3xx10^(14)Hz. If light...

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  19. A and B are two metals with threshold frequencies 1.8xx10^(14)Hz and 2...

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