The linear momentum of a 3 MeV photon is

Options

A. `0.01eVsm^(-1)`
B. `0.02eVsm^(-1)`
C. `0.03eVsm^(-1)`
D. `0.04eVsm^(-1)`

Explanation

To find the linear momentum of a 3 MeV photon, we can follow these steps:

### Step 1: Convert the energy from MeV to Joules
Given that the energy \( E \) is 3 MeV, we first convert this to Joules.

1 MeV = \( 1.6 \times 10^{-13} \) Joules.

So,
\[ E = 3 \, \text{MeV} = 3 \times 1.6 \times 10^{-13} \, \text{J} = 4.8 \times 10^{-13} \, \text{J} \]

### Step 2: Use the formula for momentum
The linear momentum \( p \) of a photon can be calculated using the formula:
\[ p = \frac{E}{c} \]
where \( c \) is the speed of light, approximately \( 3 \times 10^8 \, \text{m/s} \).

### Step 3: Substitute the values into the formula
Now we can substitute the values we have into the momentum formula:
\[ p = \frac{4.8 \times 10^{-13} \, \text{J}}{3 \times 10^8 \, \text{m/s}} \]

### Step 4: Calculate the momentum
Perform the division:
\[ p = \frac{4.8}{3} \times 10^{-13} \times 10^{-8} \, \text{kg m/s} = 1.6 \times 10^{-21} \, \text{kg m/s} \]

### Step 5: Convert the momentum to electron volt seconds per meter
To express the momentum in terms of electron volts, we can use the conversion factor:
\[ 1 \, \text{J} = 6.242 \times 10^{12} \, \text{eV} \]
Thus,
\[ p = 1.6 \times 10^{-21} \, \text{kg m/s} \times \frac{1 \, \text{eV}}{1.6 \times 10^{-19} \, \text{J}} = 1.0 \times 10^{-2} \, \text{eV s/m} \]

### Final Answer
The linear momentum of a 3 MeV photon is \( 0.01 \, \text{eV s/m} \).

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