If h is Plank's constant. Find the momentum of a photon of wavelength 0.01Å.

Options

A. `10^(-2)`
B. h
C. `10^(2)h`
D. `10^(12)h`

Explanation

To find the momentum of a photon with a given wavelength, we can use the formula for the momentum \( p \) of a photon:

\[ p = \frac{h}{\lambda} \]

where:
- \( p \) is the momentum,
- \( h \) is Planck's constant, and
- \( \lambda \) is the wavelength of the photon.

### Step-by-Step Solution:

**Step 1: Identify the given values.**
- Wavelength \( \lambda = 0.01 \, \text{Å} \)
- Convert the wavelength from angstroms to meters:
\[ 1 \, \text{Å} = 10^{-10} \, \text{m} \]
Therefore,
\[ \lambda = 0.01 \, \text{Å} = 0.01 \times 10^{-10} \, \text{m} = 1.0 \times 10^{-12} \, \text{m} \]

**Step 2: Use Planck's constant.**
- The value of Planck's constant \( h \) is approximately:
\[ h = 6.626 \times 10^{-34} \, \text{Js} \]

**Step 3: Substitute the values into the momentum formula.**
- Plugging in the values into the momentum formula:
\[ p = \frac{h}{\lambda} = \frac{6.626 \times 10^{-34} \, \text{Js}}{1.0 \times 10^{-12} \, \text{m}} \]

**Step 4: Perform the calculation.**
- Calculate the momentum:
\[ p = 6.626 \times 10^{-34} \div 1.0 \times 10^{-12} = 6.626 \times 10^{-22} \, \text{kg m/s} \]

**Step 5: Express the result in terms of \( h \).**
- Since the question asks for the momentum in terms of \( h \):
\[ p = \frac{h}{0.01 \times 10^{-10}} = \frac{h}{0.01} \times 10^{10} = 10^{12} h \]

### Final Answer:
The momentum of the photon is:
\[ p = 10^{12} h \]