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A source S(1) is producing 10^(15) photo...

A source `S_(1)` is producing `10^(15)` photons per second of wavelength `5000Ã…`. Another source `S_(2)` is producing `1.02xx10^(15)`
wavelength 5100 A Then, `("Power of" S_(2))//("Power of"S_(1))` is equal to

A

`1.00`

B

1.02

C

1.04

D

0.98

Text Solution

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The correct Answer is:
To find the ratio of the power of two sources \( S_1 \) and \( S_2 \), we can follow these steps: ### Step 1: Write down the given data - For source \( S_1 \): - Number of photons per second, \( n_1 = 10^{15} \) - Wavelength, \( \lambda_1 = 5000 \, \text{Å} = 5000 \times 10^{-10} \, \text{m} \) - For source \( S_2 \): - Number of photons per second, \( n_2 = 1.02 \times 10^{15} \) - Wavelength, \( \lambda_2 = 5100 \, \text{Å} = 5100 \times 10^{-10} \, \text{m} \) ### Step 2: Calculate the energy of a single photon for each source The energy of a photon is given by the formula: \[ E = \frac{hc}{\lambda} \] where: - \( h \) is Planck's constant \( (6.626 \times 10^{-34} \, \text{Js}) \) - \( c \) is the speed of light \( (3 \times 10^8 \, \text{m/s}) \) For source \( S_1 \): \[ E_1 = \frac{hc}{\lambda_1} = \frac{(6.626 \times 10^{-34})(3 \times 10^8)}{5000 \times 10^{-10}} \] For source \( S_2 \): \[ E_2 = \frac{hc}{\lambda_2} = \frac{(6.626 \times 10^{-34})(3 \times 10^8)}{5100 \times 10^{-10}} \] ### Step 3: Calculate the total power for each source The power produced by each source can be calculated as: \[ P = n \cdot E \] Thus, for source \( S_1 \): \[ P_1 = n_1 \cdot E_1 = n_1 \cdot \frac{hc}{\lambda_1} \] And for source \( S_2 \): \[ P_2 = n_2 \cdot E_2 = n_2 \cdot \frac{hc}{\lambda_2} \] ### Step 4: Find the ratio of the powers To find the ratio of the powers \( \frac{P_2}{P_1} \): \[ \frac{P_2}{P_1} = \frac{n_2 \cdot E_2}{n_1 \cdot E_1} = \frac{n_2 \cdot \frac{hc}{\lambda_2}}{n_1 \cdot \frac{hc}{\lambda_1}} = \frac{n_2 \cdot \lambda_1}{n_1 \cdot \lambda_2} \] ### Step 5: Substitute the values Now substituting the values we have: \[ \frac{P_2}{P_1} = \frac{(1.02 \times 10^{15}) \cdot (5000 \, \text{Å})}{(10^{15}) \cdot (5100 \, \text{Å})} \] ### Step 6: Simplify the expression \[ = \frac{1.02 \cdot 5000}{5100} \] \[ = \frac{5100}{5100} = 1 \] ### Final Result Thus, the ratio of the power of \( S_2 \) to the power of \( S_1 \) is: \[ \frac{P_2}{P_1} = 1 \]

To find the ratio of the power of two sources \( S_1 \) and \( S_2 \), we can follow these steps: ### Step 1: Write down the given data - For source \( S_1 \): - Number of photons per second, \( n_1 = 10^{15} \) - Wavelength, \( \lambda_1 = 5000 \, \text{Å} = 5000 \times 10^{-10} \, \text{m} \) - For source \( S_2 \): ...
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