A permanent magnet in the shape of a thin cylinder of length 50 cm has intensity of magnetisaton `10^(6)Am^(-1)`. The magnetisation current is

Options

A. `5xx10^(5)A`
B. `6xx10^(5)A`
C. `5xx10^(4)A`
D. `6xx10^(5)A`

Explanation

To find the magnetization current for a permanent magnet in the shape of a thin cylinder, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values**:
- Length of the cylinder, \( L = 50 \, \text{cm} = 0.5 \, \text{m} \) (conversion from cm to m)
- Intensity of magnetization, \( M = 10^6 \, \text{A/m} \)

2. **Understand the Formula**:
The magnetization current \( I_M \) can be calculated using the formula:
\[ I_M = M \times L \]
where \( M \) is the intensity of magnetization and \( L \) is the length of the magnet.

3. **Substitute the Values into the Formula**:
Substitute the values of \( M \) and \( L \) into the formula:
\[ I_M = (10^6 \, \text{A/m}) \times (0.5 \, \text{m}) \]

4. **Calculate the Magnetization Current**:
Perform the multiplication:
\[ I_M = 10^6 \times 0.5 = 5 \times 10^5 \, \text{A} \]

5. **Final Answer**:
The magnetization current is:
\[ I_M = 5 \times 10^5 \, \text{A} \]