A permanent magnet in the shape of a thin cylinder of length 10 cm has magnetisation `(M) = 10^(6)Am^(-1)`. It's magnetization current `I_(m)` is

Options

A. `10^(5)A`
B. `10^(6)A`
C. `10^(7)A`
D. `10^(8)A`

Explanation

To find the magnetization current \( I_m \) for the given permanent magnet, we can follow these steps:

### Step 1: Identify the given values
- Magnetization \( M = 10^6 \, \text{A/m} \)
- Length of the cylinder \( L = 10 \, \text{cm} = 0.1 \, \text{m} \) (conversion from cm to m)

### Step 2: Understand the relationship between magnetization current and magnetization
The formula that relates magnetization current \( I_m \) to magnetization \( M \) and length \( L \) is given by:
\[ M = \frac{I_m}{L} \]
From this, we can rearrange the formula to find \( I_m \):
\[ I_m = M \times L \]

### Step 3: Substitute the known values into the formula
Now, we can substitute the values of \( M \) and \( L \) into the equation:
\[ I_m = (10^6 \, \text{A/m}) \times (0.1 \, \text{m}) \]

### Step 4: Calculate the magnetization current
Perform the multiplication:
\[ I_m = 10^6 \times 0.1 = 10^5 \, \text{A} \]

### Step 5: State the final answer
Thus, the magnetization current \( I_m \) is:
\[ I_m = 10^5 \, \text{A} \]

### Final Answer:
The magnetization current \( I_m \) is \( 10^5 \, \text{A} \).

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