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The magnetic susceptibility of a paramag...

The magnetic susceptibility of a paramagnetic material at `-73^(@)C "is" 0.0075`, its value at `-173^(@)C` will be

A

0.045

B

0.03

C

0.015

D

0.0075

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The correct Answer is:
To solve the problem, we will use the relationship between magnetic susceptibility and temperature for paramagnetic materials. The formula we will use is: \[ \frac{\chi_1}{\chi_2} = \frac{T_2}{T_1} \] where: - \(\chi_1\) is the magnetic susceptibility at temperature \(T_1\), - \(\chi_2\) is the magnetic susceptibility at temperature \(T_2\). ### Step 1: Convert the temperatures from Celsius to Kelvin We need to convert the given temperatures from Celsius to Kelvin using the formula: \[ T(K) = T(°C) + 273 \] For \(T_1 = -73°C\): \[ T_1 = -73 + 273 = 200 \, K \] For \(T_2 = -173°C\): \[ T_2 = -173 + 273 = 100 \, K \] ### Step 2: Substitute the known values into the formula We know: - \(\chi_1 = 0.0075\), - \(T_1 = 200 \, K\), - \(T_2 = 100 \, K\). Now we can substitute these values into the equation: \[ \frac{0.0075}{\chi_2} = \frac{100}{200} \] ### Step 3: Simplify the equation The right side simplifies to: \[ \frac{100}{200} = \frac{1}{2} \] So the equation becomes: \[ \frac{0.0075}{\chi_2} = \frac{1}{2} \] ### Step 4: Solve for \(\chi_2\) Cross-multiplying gives: \[ 0.0075 \cdot 2 = \chi_2 \] Calculating this gives: \[ \chi_2 = 0.015 \] ### Final Answer The magnetic susceptibility of the paramagnetic material at \(-173°C\) is \(0.015\). ---

To solve the problem, we will use the relationship between magnetic susceptibility and temperature for paramagnetic materials. The formula we will use is: \[ \frac{\chi_1}{\chi_2} = \frac{T_2}{T_1} \] where: - \(\chi_1\) is the magnetic susceptibility at temperature \(T_1\), ...
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