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A drunkard is walking along a straight r...

A drunkard is walking along a straight road. He takes five steps forward and three steps backward and so on. Each step is `1 m` long and takes `1 s`. There is a pit on the road `11 m`, away from the starting point. The drunkard will fall into the pit after.

A

21 s

B

29 s

C

31 s

D

37 s

Text Solution

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The correct Answer is:
To solve the problem of the drunkard walking along a straight road and falling into a pit, we can break it down into steps: ### Step-by-Step Solution: 1. **Understand the Drunkard's Movement:** The drunkard takes 5 steps forward and then 3 steps backward. Each step is 1 meter long and takes 1 second. 2. **Calculate the Net Movement in One Cycle:** - In one complete cycle (5 steps forward and 3 steps backward): - Forward distance = 5 m - Backward distance = 3 m - Net distance covered in one cycle = Forward distance - Backward distance = 5 m - 3 m = 2 m. 3. **Determine the Time Taken for One Cycle:** - Total steps in one cycle = 5 (forward) + 3 (backward) = 8 steps. - Since each step takes 1 second, the total time for one cycle = 8 seconds. 4. **Calculate the Number of Cycles to Reach the Pit:** - The pit is located 11 m away from the starting point. - After each cycle, the drunkard moves 2 m forward. - To find the number of complete cycles needed to reach or exceed 11 m: - Distance after n cycles = 2n. - We need to find n such that 2n ≥ 11. - Solving for n: n = 11/2 = 5.5 cycles. - Since the drunkard cannot complete half a cycle, he will complete 5 cycles. 5. **Calculate the Distance After 5 Cycles:** - After 5 cycles, the distance covered = 2 * 5 = 10 m. - Time taken for 5 cycles = 8 seconds/cycle * 5 cycles = 40 seconds. 6. **Determine the Remaining Distance to the Pit:** - After 5 cycles, the drunkard is at 10 m. The pit is at 11 m, so he has 1 m left to walk. 7. **Final Step to the Pit:** - In the next cycle, he will take 5 steps forward (1 m each), reaching 15 m, and then take 3 steps backward (1 m each), ending up at 12 m. - However, since he only needs to walk 1 more meter to reach the pit, he will fall into the pit after taking 1 more step forward. 8. **Calculate the Total Time Until He Falls:** - He has already taken 40 seconds for the first 5 cycles. - He will take 1 more second to take that final step forward into the pit. - Total time = 40 seconds + 1 second = 41 seconds. ### Conclusion: The drunkard will fall into the pit after **41 seconds**.

To solve the problem of the drunkard walking along a straight road and falling into a pit, we can break it down into steps: ### Step-by-Step Solution: 1. **Understand the Drunkard's Movement:** The drunkard takes 5 steps forward and then 3 steps backward. Each step is 1 meter long and takes 1 second. 2. **Calculate the Net Movement in One Cycle:** ...
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