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A body starts from rest and moves with ...

A body starts from rest and moves with constant acceleration for t s. It travels a distance `x_1` in first half of time and `x_2` in next half of time, then

A

`x_2 = 3x_1`

B

`x_2 = x_1`

C

`x_2 = 4x_1`

D

`x_2 = 2x_1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the motion of the body in two halves of the time interval \( t \). ### Step 1: Understanding the motion The body starts from rest and moves with constant acceleration \( a \) for a total time \( t \). The distance traveled in the first half of the time \( (t/2) \) is \( x_1 \) and in the second half of the time \( (t/2) \) is \( x_2 \). ### Step 2: Calculate the velocity at the end of the first half Using the first equation of motion: \[ V_1 = U + a \cdot t_1 \] where \( U = 0 \) (initial velocity), \( t_1 = \frac{t}{2} \). Thus, \[ V_1 = 0 + a \cdot \frac{t}{2} = \frac{a t}{2} \] ### Step 3: Calculate the distance \( x_1 \) for the first half Using the third equation of motion: \[ x_1 = U \cdot t_1 + \frac{1}{2} a t_1^2 \] Substituting \( U = 0 \) and \( t_1 = \frac{t}{2} \): \[ x_1 = 0 + \frac{1}{2} a \left(\frac{t}{2}\right)^2 = \frac{1}{2} a \cdot \frac{t^2}{4} = \frac{a t^2}{8} \] ### Step 4: Calculate the velocity at the end of the total time Using the first equation of motion again for the total time \( t \): \[ V = U + a \cdot t = 0 + a \cdot t = a t \] ### Step 5: Calculate the distance \( x_2 \) for the second half Now, we need to calculate the distance traveled from point B to point C (the second half): Using the third equation of motion: \[ x_2 = V_1 \cdot t_2 + \frac{1}{2} a t_2^2 \] where \( t_2 = \frac{t}{2} \) and \( V_1 = \frac{a t}{2} \): \[ x_2 = \left(\frac{a t}{2}\right) \cdot \frac{t}{2} + \frac{1}{2} a \left(\frac{t}{2}\right)^2 \] Calculating this: \[ x_2 = \frac{a t^2}{4} + \frac{1}{2} a \cdot \frac{t^2}{4} = \frac{a t^2}{4} + \frac{a t^2}{8} = \frac{2a t^2}{8} + \frac{a t^2}{8} = \frac{3a t^2}{8} \] ### Step 6: Relate \( x_1 \) and \( x_2 \) Now we have: - \( x_1 = \frac{a t^2}{8} \) - \( x_2 = \frac{3a t^2}{8} \) We can express \( x_2 \) in terms of \( x_1 \): \[ x_2 = 3x_1 \] ### Conclusion Thus, the relationship between the distances traveled in the two halves of the time is: \[ x_2 = 3x_1 \]

To solve the problem step by step, we will analyze the motion of the body in two halves of the time interval \( t \). ### Step 1: Understanding the motion The body starts from rest and moves with constant acceleration \( a \) for a total time \( t \). The distance traveled in the first half of the time \( (t/2) \) is \( x_1 \) and in the second half of the time \( (t/2) \) is \( x_2 \). ### Step 2: Calculate the velocity at the end of the first half Using the first equation of motion: \[ ...
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