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A body A starts from rest with an accele...

A body `A` starts from rest with an acceleration `a_1`. After `2` seconds, another body `B` starts from rest with an acceleration `a_2`. If they travel equal distances in the `5^(th)` second, after the start of `A`, then the ratio `a_1 : a_2` is equal to :

A

0.21458333333333

B

0.21319444444444

C

0.37847222222222

D

0.37986111111111

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The correct Answer is:
To solve the problem, we need to find the ratio of the accelerations \( a_1 \) and \( a_2 \) of two bodies \( A \) and \( B \) that start from rest and travel equal distances in the 5th second after the start of \( A \). ### Step-by-Step Solution: 1. **Understanding the Problem**: - Body \( A \) starts from rest with acceleration \( a_1 \) at \( t = 0 \). - Body \( B \) starts from rest with acceleration \( a_2 \) at \( t = 2 \) seconds. - We need to find the ratio \( \frac{a_1}{a_2} \) given that both bodies travel equal distances in the 5th second after the start of \( A \). 2. **Distance Covered in the nth Second**: - The formula for the distance covered by an object starting from rest in the nth second is given by: \[ s_n = \frac{1}{2} a (2n - 1) \] - Here, \( s_n \) is the distance covered in the nth second, and \( a \) is the acceleration. 3. **Distance Covered by Body A in the 5th Second**: - For body \( A \) (where \( n = 5 \)): \[ s_A = \frac{1}{2} a_1 (2 \times 5 - 1) = \frac{1}{2} a_1 (10 - 1) = \frac{9}{2} a_1 \] 4. **Distance Covered by Body B in the 3rd Second**: - Body \( B \) starts at \( t = 2 \) seconds, so by the time it reaches the 5th second, it has been moving for \( 5 - 2 = 3 \) seconds. - For body \( B \) (where \( n = 3 \)): \[ s_B = \frac{1}{2} a_2 (2 \times 3 - 1) = \frac{1}{2} a_2 (6 - 1) = \frac{5}{2} a_2 \] 5. **Setting Distances Equal**: - Since both bodies travel equal distances in the 5th second: \[ s_A = s_B \] \[ \frac{9}{2} a_1 = \frac{5}{2} a_2 \] 6. **Solving for the Ratio**: - To find the ratio \( \frac{a_1}{a_2} \), we can rearrange the equation: \[ 9 a_1 = 5 a_2 \] \[ \frac{a_1}{a_2} = \frac{5}{9} \] ### Final Answer: The ratio \( a_1 : a_2 \) is \( 5 : 9 \).

To solve the problem, we need to find the ratio of the accelerations \( a_1 \) and \( a_2 \) of two bodies \( A \) and \( B \) that start from rest and travel equal distances in the 5th second after the start of \( A \). ### Step-by-Step Solution: 1. **Understanding the Problem**: - Body \( A \) starts from rest with acceleration \( a_1 \) at \( t = 0 \). - Body \( B \) starts from rest with acceleration \( a_2 \) at \( t = 2 \) seconds. - We need to find the ratio \( \frac{a_1}{a_2} \) given that both bodies travel equal distances in the 5th second after the start of \( A \). ...
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