Stopping distance of a moving vehicle is directly proportional to

Options

A. Square of initial velocity
B. Square of initial acceleration
C. The initial velocity
D. The initial acceleration

Answer

(a)

Explanation

Let the distance travelled by the vehicle before it stops be `d_s`, then using `v^(2) = u^(2)` - 2ax
put v = 0, x = `d_s`(stopping distance) we get `d_s` = `u^(2)/2a`
Thus, the stopping distance is proportional to the square of the initial velocity.