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A flywheel rotating at 420 rpm slows dow...

A flywheel rotating at `420` rpm slows down at a constant rate of `2 rad s^(-2)`. The time required to stop the flywheel is:

A

22 s

B

11 s

C

44 s

D

12 s

Text Solution

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The correct Answer is:
To solve the problem of determining the time required to stop the flywheel, we can follow these steps: ### Step 1: Convert the initial angular velocity from rpm to rad/s The initial angular velocity (ω_initial) is given as 420 rpm. We need to convert this to radians per second. \[ \omega_{\text{initial}} = 420 \, \text{rpm} \times \frac{2\pi \, \text{radians}}{1 \, \text{rotation}} \times \frac{1 \, \text{minute}}{60 \, \text{seconds}} \] Calculating this gives: \[ \omega_{\text{initial}} = 420 \times \frac{2\pi}{60} = 14\pi \, \text{rad/s} \] ### Step 2: Identify the final angular velocity and angular acceleration The flywheel comes to a stop, so the final angular velocity (ω_final) is: \[ \omega_{\text{final}} = 0 \, \text{rad/s} \] The angular acceleration (α) is given as a constant rate of slowing down: \[ \alpha = -2 \, \text{rad/s}^2 \] ### Step 3: Use the angular motion equation We can use the first equation of angular motion, which relates initial angular velocity, final angular velocity, angular acceleration, and time: \[ \omega_{\text{final}} = \omega_{\text{initial}} + \alpha t \] Substituting the known values: \[ 0 = 14\pi + (-2)t \] ### Step 4: Solve for time (t) Rearranging the equation to solve for t: \[ 2t = 14\pi \] \[ t = \frac{14\pi}{2} = 7\pi \, \text{seconds} \] ### Step 5: Calculate the numerical value of time To get the numerical value, we can use the approximation of π: \[ t \approx 7 \times 3.14 \approx 22 \, \text{seconds} \] ### Conclusion Therefore, the time required to stop the flywheel is: \[ \text{Time} = 22 \, \text{seconds} \] ---

To solve the problem of determining the time required to stop the flywheel, we can follow these steps: ### Step 1: Convert the initial angular velocity from rpm to rad/s The initial angular velocity (ω_initial) is given as 420 rpm. We need to convert this to radians per second. \[ \omega_{\text{initial}} = 420 \, \text{rpm} \times \frac{2\pi \, \text{radians}}{1 \, \text{rotation}} \times \frac{1 \, \text{minute}}{60 \, \text{seconds}} \] ...
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