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The work done in bringing a unit positiv...

The work done in bringing a unit positive charge from infinite distance to a point at distance x from a positive charge Q is W. Then the potential `phi` at that point is

A

`(WQ)/(x)`

B

W

C

`W/x`

D

WQ

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The correct Answer is:
To find the electric potential \( \phi \) at a point located at a distance \( x \) from a positive charge \( Q \), given that the work done in bringing a unit positive charge from infinity to that point is \( W \), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Electric Potential**: The electric potential \( \phi \) at a point in an electric field is defined as the work done per unit charge in bringing a positive test charge from infinity to that point. 2. **Work Done Definition**: According to the problem, the work done in bringing a unit positive charge from infinity to a point at distance \( x \) from charge \( Q \) is given as \( W \). 3. **Relating Work Done to Potential**: By definition, the potential \( \phi \) at a point is equal to the work done \( W \) in bringing a unit positive charge from infinity to that point. Therefore, we can express this relationship mathematically as: \[ \phi = W \] 4. **Conclusion**: Thus, the potential \( \phi \) at the point located at distance \( x \) from the charge \( Q \) is simply equal to the work done \( W \). ### Final Answer: \[ \phi = W \] ---
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