A copper plate of thickness b is placed inside a parallel plate capacitor of plate distance d and area A as shown in figure. The capacitance of capacitor is

Options

A. `(epsi_(0)A)/(d+(b)/(2))`
B. `(epsi_(0)A)/(2d)`
C. `(epsi_(0)A)/(d-b)`
D. `(2 epsi_(0)A)/(d+(b)/(2))`

Answer

C

Explanation

As capacitance `C_(o) = (epsi_(0)A)/(d)`
`therefore ` after inserting copper plate `C = (epsi_(0)A)/(d-b)`