A capacitor is charged through a potential difference of 200 V, when 0.1C charge is stored in it. The amount of energy released by it, when it is discharged is

Options

A. 5 J
B. 10 J
C. 20 J
D. 2.5 J

Explanation

To find the amount of energy released by a capacitor when it is discharged, we can use the formula for the energy stored in a capacitor. Here’s a step-by-step solution:

### Step 1: Identify the formula for energy stored in a capacitor
The energy (U) stored in a capacitor is given by the formula:
\[ U = \frac{1}{2} C V^2 \]
where:
- \( U \) is the energy stored,
- \( C \) is the capacitance,
- \( V \) is the voltage across the capacitor.

However, we can also express this in terms of charge (Q):
\[ U = \frac{1}{2} Q V \]
where:
- \( Q \) is the charge stored in the capacitor.

### Step 2: Substitute the known values
From the problem, we know:
- \( Q = 0.1 \, \text{C} \)
- \( V = 200 \, \text{V} \)

Now we can substitute these values into the formula:
\[ U = \frac{1}{2} \times Q \times V \]
\[ U = \frac{1}{2} \times 0.1 \, \text{C} \times 200 \, \text{V} \]

### Step 3: Calculate the energy
Now we perform the calculation:
\[ U = \frac{1}{2} \times 0.1 \times 200 \]
\[ U = \frac{1}{2} \times 20 \]
\[ U = 10 \, \text{J} \]

### Step 4: Conclusion
The amount of energy released by the capacitor when it is discharged is:
\[ \text{Energy released} = 10 \, \text{J} \]