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A parallel plate capacitor has a uniform...

A parallel plate capacitor has a uniform electric field E in the space between the the plates. If the distance between the plates is d and area of each plate is A, the energy stored in the capacitor is

A

`(1)/(2)epsi_(0)E^(2)`

B

`(E^(2)Ad)/(epsi_(0))`

C

`1/2epsi_(0)E^(2)Ad`

D

`eisi_(0)E^(2)Ad`

Text Solution

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The correct Answer is:
To find the energy stored in a parallel plate capacitor given the uniform electric field \( E \), distance between the plates \( d \), and area of each plate \( A \), we can follow these steps: ### Step 1: Understand the relationship between capacitance, voltage, and energy The energy \( U \) stored in a capacitor can be expressed as: \[ U = \frac{1}{2} C V^2 \] where \( C \) is the capacitance and \( V \) is the voltage across the capacitor. ### Step 2: Determine the capacitance of a parallel plate capacitor The capacitance \( C \) of a parallel plate capacitor is given by the formula: \[ C = \frac{\varepsilon_0 A}{d} \] where \( \varepsilon_0 \) is the permittivity of free space, \( A \) is the area of the plates, and \( d \) is the distance between the plates. ### Step 3: Relate the electric field to voltage The electric field \( E \) between the plates is related to the voltage \( V \) and the distance \( d \) by the equation: \[ E = \frac{V}{d} \] From this, we can express the voltage \( V \) as: \[ V = E \cdot d \] ### Step 4: Substitute the expressions for capacitance and voltage into the energy formula Now, substituting \( C \) and \( V \) into the energy formula: \[ U = \frac{1}{2} \left(\frac{\varepsilon_0 A}{d}\right) (E \cdot d)^2 \] ### Step 5: Simplify the expression Substituting \( V \) into the energy equation gives: \[ U = \frac{1}{2} \left(\frac{\varepsilon_0 A}{d}\right) (E^2 d^2) \] This simplifies to: \[ U = \frac{1}{2} \varepsilon_0 A E^2 d \] ### Step 6: Final expression for energy stored in the capacitor Thus, the energy stored in the parallel plate capacitor is: \[ U = \frac{1}{2} \varepsilon_0 A E^2 d \] ### Final Result The energy stored in the capacitor is: \[ U = \frac{1}{2} \varepsilon_0 A E^2 d \] ---

To find the energy stored in a parallel plate capacitor given the uniform electric field \( E \), distance between the plates \( d \), and area of each plate \( A \), we can follow these steps: ### Step 1: Understand the relationship between capacitance, voltage, and energy The energy \( U \) stored in a capacitor can be expressed as: \[ U = \frac{1}{2} C V^2 \] where \( C \) is the capacitance and \( V \) is the voltage across the capacitor. ...
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  11. Assertion: Increasing the charge on the plates of a capacitor means in...

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