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A rectangular coil ABCD is hung from one...

A rectangular coil ABCD is hung from one side of a balance as shown in higure. A 500 g mass is added to the other arm to balance the weight of the coil. A current of 9.8 A is passed through the coil and a constant magnetic field of 0.4 T acting inward (in xz plane) is switched on such that only arm CD of length 1.5 cm lies in the field. The additional mass m must be added to regain the balance is

A

4g

B

5g

C

6g

D

7g

Text Solution

Verified by Experts

The correct Answer is:
C
In absence of magnetic field the weight added in one pan balances the rectangular coil in the other pen of balance,
`therefore" "Mgl=W_("coil")l or W_("coil")=Mg=0.5xx9.8N`
When current I is passed through the coil and the magnetic field is switched on.
Let m mass be added in the first pan to regain the balance Then `Mgl+mgl=W_("coil")l+"IBL sin "90^(@)l`
`mgl = IBLl`
`"or "m=(IBL)/(g)=(9.8xx0.4xx1.5xx10^(-2))/(9.8)=0.6xx10^(-2)kg`
`=6xx10^(-3)kg=6g`
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