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A particle with charge q, moving with a ...

A particle with charge `q`, moving with a momentum `p`, enters a uniform magnetic field normally. The magnetic field has magnitude `B` and is confined to a region of width `d`, where `dlt(p)/(Bq)`. If the particle is deflected by an angle `theta` in crosing the field then

A

`sin theta=(BQd)/(p)`

B

`sin theta=(P)/(BQd)`

C

`sin theta=(Bp)/(Qd)`

D

`sin theta=(pd)/(BQ)`

Text Solution

Verified by Experts

The correct Answer is:
A
A to D is part of circle with center C and radius CD=r, `mv = p = BQr` or `r=p/(BQ)`
`sintheta = (ED)/(CD) = d/r = (BQd)/(P)`
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