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Two nuclei have their mass numbers in th...

Two nuclei have their mass numbers in the ratio of 1:3. The ratio of their nuclear densities would be

A

`(3)^(1//3):1`

B

`1:1`

C

`1:3`

D

`3:1`

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To find the ratio of nuclear densities of two nuclei with mass numbers in the ratio of 1:3, we can follow these steps: ### Step 1: Understand Nuclear Density Nuclear density is defined as the mass of the nucleus divided by its volume. The formula for density (\( \rho \)) is given by: \[ \rho = \frac{\text{mass}}{\text{volume}} \] ### Step 2: Define Mass and Volume of Nuclei Let the mass numbers of the two nuclei be \( A \) and \( 3A \). The mass of a nucleus can be approximated as: \[ \text{mass} = A \times m_p \] where \( m_p \) is the mass of a proton (approximately \( 1.67 \times 10^{-27} \) kg). The volume \( V \) of a nucleus can be modeled as a sphere, which is given by: \[ V = \frac{4}{3} \pi R^3 \] The radius \( R \) of a nucleus can be approximated using the formula: \[ R = R_0 A^{1/3} \] where \( R_0 \) is a constant (approximately \( 1.1 \times 10^{-15} \) m). ### Step 3: Calculate the Volume for Each Nucleus For nucleus with mass number \( A \): \[ R_A = R_0 A^{1/3} \] \[ V_A = \frac{4}{3} \pi (R_0 A^{1/3})^3 = \frac{4}{3} \pi R_0^3 A \] For nucleus with mass number \( 3A \): \[ R_{3A} = R_0 (3A)^{1/3} = R_0 \cdot 3^{1/3} A^{1/3} \] \[ V_{3A} = \frac{4}{3} \pi (R_0 \cdot 3^{1/3} A^{1/3})^3 = \frac{4}{3} \pi R_0^3 (3A) \] ### Step 4: Calculate the Densities Now we can calculate the densities for both nuclei. For nucleus with mass number \( A \): \[ \rho_A = \frac{A \cdot m_p}{\frac{4}{3} \pi R_0^3 A} = \frac{3 m_p}{4 \pi R_0^3} \] For nucleus with mass number \( 3A \): \[ \rho_{3A} = \frac{3A \cdot m_p}{\frac{4}{3} \pi R_0^3 (3A)} = \frac{3 m_p}{4 \pi R_0^3} \] ### Step 5: Compare Densities From the calculations, we see that: \[ \rho_A = \rho_{3A} = \frac{3 m_p}{4 \pi R_0^3} \] ### Conclusion The ratio of the nuclear densities of the two nuclei is: \[ \frac{\rho_A}{\rho_{3A}} = 1 \] Thus, the ratio of their nuclear densities is **1:1**.

To find the ratio of nuclear densities of two nuclei with mass numbers in the ratio of 1:3, we can follow these steps: ### Step 1: Understand Nuclear Density Nuclear density is defined as the mass of the nucleus divided by its volume. The formula for density (\( \rho \)) is given by: \[ \rho = \frac{\text{mass}}{\text{volume}} \] ...
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NCERT FINGERTIPS ENGLISH-NUCLEI-Assertion And Reason
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  2. Assertion:The whole mass of the atom is concentrated in the nucleus. ...

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  3. Assertion : The radius of a nucleus determined by electron scattering ...

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  4. Assertion:Isotopes of an element can be separated by using a mass spec...

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  5. Assertion:When a nucleus is in an excited state, it can make a transit...

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  6. Assertion:Binding energy per nucleon is nearly constant for element i...

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  7. Assertion:Nuclear force between neutron-neutron, proton-neutron and pr...

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  8. Assertion:A free neutron is unstable Reason : Free neutron disintegr...

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  9. Assertion:The detection of neutrinos is extremely difficult . Reason...

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  10. Assertion:An alpha-particle is emitted when uranium 238 decays into th...

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  11. Assertion:The mass of beta-particles when they are emitted is higher t...

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  12. Assertion:Neutrons penetrate matter more readily as compared to proton...

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  13. Assertion:There occurs a chain reaction when uranium is bombarded wit...

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  14. Assertion:Fusion of hydrogen nuclei into helium nuclei is the source o...

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  15. Assertion:Nuclear sources will give a million times larger energy than...

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  16. Assertion:Naturally , thermonuclear fusion reaction is not possible on...

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