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During negative B decay, an anti- neutri...

During negative B decay, an anti- neutrino is also emmited along with the ejected electron. Then

A

only linear momentum will be conserved

B

total linear momentum and total anuglar momentum but not total energy will be conserved

C

total linear momentum and total energy but not total angular momentum will be conserved

D

total linear momentum , total angular momentum and total energy will be conserved.

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The correct Answer is:
d
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During a negative beta decay,

During a negative beta decay,

During alpha-decay , a nucleus decays by emitting an alpha -particle ( a helium nucleus ._2He^4 ) according to the equation ._Z^AX to ._(Z-2)^(A-4)Y+._2^4He+Q In this process, the energy released Q is shared by the emitted alpha -particle and daughter nucleus in the form of kinetic energy . The energy Q is divided in a definite ratio among the alpha -particle and the daughter nucleus . A nucleus that decays spontaneously by emitting an electron or a positron is said to undergo beta -decay .This process also involves a release of definite energy . Initially, the beta -decay was represented as ._Z^AX to ._(Z+1)^AY + e^(-)"(electron)"+Q According to this reaction, the energy released during each decay must be divided in definite ratio by the emitted e' ( beta -particle) and the daughter nucleus. While , in alpha decay, it has been found that every emitted alpha -particle has the same sharply defined kinetic energy. It is not so in case of beta -decay . The energy of emitted electrons or positrons is found to vary between zero to a certain maximum value. Wolfgang Pauli first suggested the existence of neutrinoes in 1930. He suggested that during beta -decay, a third particle is also emitted. It shares energy with the emitted beta particles and thus accounts for the energy distribution. During beta^+ decay (positron emission) a proton in the nucleus is converted into a neutron, positron and neutrino. The reaction is correctly represented as

During alpha-decay , a nucleus decays by emitting an alpha -particle ( a helium nucleus ._2He^4 ) according to the equation ._Z^AX to ._(Z-2)^(A-4)Y+._2^4He+Q In this process, the energy released Q is shared by the emitted alpha -particle and daughter nucleus in the form of kinetic energy . The energy Q is divided in a definite ratio among the alpha -particle and the daughter nucleus . A nucleus that decays spontaneously by emitting an electron or a positron is said to undergo beta -decay .This process also involves a release of definite energy . Initially, the beta -decay was represented as ._Z^AX to ._(Z+1)^AY + e^(-)"(electron)"+Q According to this reaction, the energy released during each decay must be divided in definite ratio by the emitted e' ( beta -particle) and the daughter nucleus. While , in alpha decay, it has been found that every emitted alpha -particle has the same sharply defined kinetic energy. It is not so in case of beta -decay . The energy of emitted electrons or positrons is found to vary between zero to a certain maximum value. Wolfgang Pauli first suggested the existence of neutrinoes in 1930. He suggested that during beta -decay, a third particle is also emitted. It shares energy with the emitted beta particles and thus accounts for the energy distribution. The beta particles (positron) are emitted with different kinetic energies because

During alpha-decay , a nucleus decays by emitting an alpha -particle ( a helium nucleus ._2He^4 ) according to the equation ._Z^AX to ._(Z-2)^(A-4)Y+._2^4He+Q In this process, the energy released Q is shared by the emitted alpha -particle and daughter nucleus in the form of kinetic energy . The energy Q is divided in a definite ratio among the alpha -particle and the daughter nucleus . A nucleus that decays spontaneously by emitting an electron or a positron is said to undergo beta -decay .This process also involves a release of definite energy . Initially, the beta -decay was represented as ._Z^AX to ._(Z+1)^AY + e^(-)"(electron)"+Q According to this reaction, the energy released during each decay must be divided in definite ratio by the emitted e' ( beta -particle) and the daughter nucleus. While , in alpha decay, it has been found that every emitted alpha -particle has the same sharply defined kinetic energy. It is not so in case of beta -decay . The energy of emitted electrons or positrons is found to vary between zero to a certain maximum value. Wolfgang Pauli first suggested the existence of neutrinoes in 1930. He suggested that during beta -decay, a third particle is also emitted. It shares energy with the emitted beta particles and thus accounts for the energy distribution. When a nucleus of mass number A at rest decays emitting an alpha -particle , the daugther nucleus recoils with energy K . What is the Q value of the reaction ?

A neutron initially at rest, decays into a proton, an electron and an antineutrino. The ejected electron has a momentum of 1.4xx10^-26 kg-m/s and that of antineutrino 6.4xx10^-27 kg-m/s. Find the recoil speed of the proton a. if the electron and the antineutrino are ejected along the same direction and b. if they are ejected along perpendicular directions. Mass of the proton 1.67xx10^-27 kg.

The beta -decay process, discovered around 1900 , is basically the decay of a neutron (n) , In the laboratory, a proton (p) and an electron (e^(-)) are observed as the decay products of the neutron. Therefore, considering the decay of a neutron as a tro-body dcay process, it was observed that the electron kinetic energy has a continuous spectrum. Considering a three-body decay process i.e., n rarr p + e^(-)+overset(-)v_(e ) , around 1930 , Pauli explained the observed electron energy spectrum. Assuming the anti-neutrino (overset(-)V_(e )) to be massless and possessing negligible energy, and neutron to be at rest, momentum and energy conservation principles are applied. From this calculation, the maximum kinetic energy of the electron is 0.8xx10^(6)eV . The kinetic energy carried by the proton is only the recoil energy. What is the maximum energy of the anti-neutrino?

The beta -decay process, discovered around 1900 , is basically the decay of a neutron (n) , In the laboratory, a proton (p) and an electron (e^(-)) are observed as the decay products of the neutron. Therefore, considering the decay of a neutron as a tro-body dcay process, it was observed that the electron kinetic energy has a continuous spectrum. Considering a three-body decay process i.e., n rarr p + e^(-)+overset(-)v_(e ) , around 1930 , Pauli explained the observed electron energy spectrum. Assuming the anti-neutrino (overset(-)V_(e )) to be massless and possessing negligible energy, and neutron to be at rest, momentum and energy conservation principles are applied. From this calculation, the maximum kinetic energy of the electron is 0.8xx10^(6)eV . The kinetic energy carried by the proton is only the recoil energy. If the anti-neutrino has a mass of 3eV//c^(2) (where c is the speed of light) instead of zero mass, what should be the range of the kinetic energy, K of the electron?

STATEMENT-1 : In the decay of a free neutron at rest, into a proton and electron, it has been predicated that a third particle must also be emitted because the emitted electrons do not have a definite kinetic energy. and STATEMENT-2 : For the simple decay of a stationary particle into two moving particles, the kinetic energies of the particle must have a sharply defined value.

During beta -decay of stationary nucleus , an electron is observed with a kinetic energy 1.0 MeV . From this ,what can be concluded about the Q-value of the decay ?

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  2. Assertion:The whole mass of the atom is concentrated in the nucleus. ...

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  3. Assertion : The radius of a nucleus determined by electron scattering ...

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  9. Assertion:The detection of neutrinos is extremely difficult . Reason...

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