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A ancleus of mass number 220, initially ...

A ancleus of mass number 220, initially at rest, emits an `alpha`-particle, If the Q-value of the reaction is 5.5 Me V, then the energy of the emitted `alpha`-particle will be

A

4.4 MeV

B

5.4 MeV

C

5.6 MeV

D

6.5 MeV

Text Solution

Verified by Experts

The correct Answer is:
b
`K_alpha = ((A-4))/A Q`
Here, A=220 , Q=5.5 MeV
`K_alpha =((220-4)/220)5.5` MeV = `(216/220)`5.5 MeV = 5.4 MeV
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