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The gravitational force between a H-atom...

The gravitational force between a H-atom and another particle of mass `m` will be given by Newton's law
`F = G (M.m)/(r^(2))`, where `r` is in km and

A

`M=m_"proton"+m_"electron"`

B

`M=m_"proton"+m_"electron"-B/c^2 ` (B=13.6 eV)

C

M is not related to the mass of hydrogen atom

D

`M=m_"proton"+m_"electron" -(|V|)/c^2`(|V|=magnitude of the potential energy of electron in the H-atom )

Text Solution

Verified by Experts

The correct Answer is:
b
Here, M=Mass of Hydrogen atom
`=m_"proton"+m_"electron"-B/C^2`
where B is binding energy of H-atom which is 13.6 eV.
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