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A particle starts moving from point (2, ...

A particle starts moving from point (2, 10, 1). Displacement for the particle is `8hati - 2hatj + hatk` . The final coordinates of the particle is

A

`(10, 8, 2)`

B

`(8, 10, 2)`

C

`(2, 10, 8)`

D

`(8, 2, 10)`

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The correct Answer is:
To find the final coordinates of the particle after its displacement, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Initial Position Vector**: The particle starts from the point (2, 10, 1). In vector form, this can be represented as: \[ \mathbf{r_1} = 2\hat{i} + 10\hat{j} + 1\hat{k} \] 2. **Identify the Displacement Vector**: The displacement given is: \[ \mathbf{d} = 8\hat{i} - 2\hat{j} + 1\hat{k} \] 3. **Set Up the Equation for Final Position Vector**: The final position vector \( \mathbf{r_2} \) can be expressed in terms of the initial position vector and the displacement: \[ \mathbf{r_2} = \mathbf{r_1} + \mathbf{d} \] 4. **Substitute the Values**: Substitute the initial position vector and the displacement vector into the equation: \[ \mathbf{r_2} = (2\hat{i} + 10\hat{j} + 1\hat{k}) + (8\hat{i} - 2\hat{j} + 1\hat{k}) \] 5. **Combine the Vectors**: Combine the components of the vectors: \[ \mathbf{r_2} = (2 + 8)\hat{i} + (10 - 2)\hat{j} + (1 + 1)\hat{k} \] \[ \mathbf{r_2} = 10\hat{i} + 8\hat{j} + 2\hat{k} \] 6. **Write the Final Coordinates**: The final coordinates of the particle are: \[ (10, 8, 2) \] ### Final Answer: The final coordinates of the particle are \( (10, 8, 2) \). ---

To find the final coordinates of the particle after its displacement, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Initial Position Vector**: The particle starts from the point (2, 10, 1). In vector form, this can be represented as: \[ \mathbf{r_1} = 2\hat{i} + 10\hat{j} + 1\hat{k} \] ...
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