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Two projectiles are fired from the same ...

Two projectiles are fired from the same point with the same speed at angles of projection `60^(@) and 30^(@)` respectively. Which one of the following is true?

A

Their range will be the same.

B

Their maximum height will be the same.

C

Their velocity at the heighest point will be the same.

D

Their time of flight will be the same.

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The correct Answer is:
To solve the problem, we need to analyze the ranges of the two projectiles fired at angles of \(60^\circ\) and \(30^\circ\) with the same initial speed \(u\). ### Step-by-Step Solution: 1. **Understanding the Range Formula**: The range \(R\) of a projectile is given by the formula: \[ R = \frac{u^2 \sin(2\theta)}{g} \] where \(u\) is the initial speed, \(\theta\) is the angle of projection, and \(g\) is the acceleration due to gravity. 2. **Calculate the Range for the First Projectile**: For the projectile fired at an angle of \(60^\circ\): \[ R_1 = \frac{u^2 \sin(2 \times 60^\circ)}{g} \] We know that \(2 \times 60^\circ = 120^\circ\), so: \[ R_1 = \frac{u^2 \sin(120^\circ)}{g} \] Using the sine value, \(\sin(120^\circ) = \sin(180^\circ - 60^\circ) = \sin(60^\circ) = \frac{\sqrt{3}}{2}\): \[ R_1 = \frac{u^2 \cdot \frac{\sqrt{3}}{2}}{g} = \frac{\sqrt{3} u^2}{2g} \] 3. **Calculate the Range for the Second Projectile**: For the projectile fired at an angle of \(30^\circ\): \[ R_2 = \frac{u^2 \sin(2 \times 30^\circ)}{g} \] We know that \(2 \times 30^\circ = 60^\circ\), so: \[ R_2 = \frac{u^2 \sin(60^\circ)}{g} \] Using the sine value, \(\sin(60^\circ) = \frac{\sqrt{3}}{2}\): \[ R_2 = \frac{u^2 \cdot \frac{\sqrt{3}}{2}}{g} = \frac{\sqrt{3} u^2}{2g} \] 4. **Comparing the Ranges**: From the calculations, we find: \[ R_1 = \frac{\sqrt{3} u^2}{2g} \quad \text{and} \quad R_2 = \frac{\sqrt{3} u^2}{2g} \] Therefore, we conclude that: \[ R_1 = R_2 \] 5. **Conclusion**: Since both projectiles have the same range, we can state that the ranges of the projectiles fired at angles \(60^\circ\) and \(30^\circ\) are equal. ### Final Answer: The correct statement is that the ranges of the two projectiles are the same. ---

To solve the problem, we need to analyze the ranges of the two projectiles fired at angles of \(60^\circ\) and \(30^\circ\) with the same initial speed \(u\). ### Step-by-Step Solution: 1. **Understanding the Range Formula**: The range \(R\) of a projectile is given by the formula: \[ R = \frac{u^2 \sin(2\theta)}{g} ...
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