A stone tied to the end of string 100cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolution in 22s, then the acceleration of the stone is

Options

A. 16 m `s^(-2)`
B. 4 m `s^(-2)`
C. 12 m `s^(-2)`
D. 8 m `s^(-2)`

Answer

A

Explanation

Here, `r=100cm=1m`
Frequency, `v=(14)/(22)rps:.omega=2piv=2xx(22)/(7)xx(14)/(22)=4rads^(-1)`
The acceleration of the stone is
`a_(c)=omega^(2)r=(4)^(2)(1)=16ms^(-1)`