A particle is moving on a circular path with a constant speed `v`. Its change of velocity as it moves from A to B is:

Options

A. `2v sin (2theta)`
B. zero
C. `2v sin ((theta)/(2))`
D. `2 v cos ((theta)/(2))`

Answer

C

Explanation

`|vec(v)|=|vec(v)|=v`
`Deltavec(v)=vec(v)-vec(v)`
`:.|Deltavec(v)|=sqrt(v^(2)+v^(2)-2v^(2)costheta)`
`=sqrt(2v^(2)(1-costheta))=2vsin""(theta)/(2)`