Fill in the blanks :
(i) `Ca_(3)P_(2)+6HClrarr 3CaCl_(2) + ....p ....`
(ii) `P_(4) + 3NaOH + 3H_(2)O rarr ...q...+3 NaH_(2)PO_(2)`
(iii) `PH_(4)I + KOH rarr KI + H_(2)O+...r...` p, q and r respectively are

Options

A. a. `PH_(3), H_(3)PO_(3), Pl_(3)`
B. b. `PH_(3), PH_(3), PH_(3)`
C. c. `PCl_(3), H_(3)PO_(4),PH_(3)`
D. d. `PCl_(5), PH_(3), P_(4)O_(6)`

Answer

To solve the given question, we need to identify the products of the chemical reactions provided. Let's break down each reaction step by step.

### Step 1: Analyze the first reaction
The first reaction given is:
\[ \text{Ca}_3\text{P}_2 + 6 \text{HCl} \rightarrow 3 \text{CaCl}_2 + \ldots \text{p} \ldots \]

1. **Identify the reactants**:
- Calcium phosphide (\( \text{Ca}_3\text{P}_2 \))
- Hydrochloric acid (\( \text{HCl} \))

2. **Determine the products**:
- The reaction of calcium phosphide with hydrochloric acid produces calcium chloride (\( \text{CaCl}_2 \)) and phosphine (\( \text{PH}_3 \)).

3. **Fill in the blank**:
- Therefore, \( \text{p} = \text{PH}_3 \).

### Step 2: Analyze the second reaction
The second reaction given is:
\[ \text{P}_4 + 3 \text{NaOH} + 3 \text{H}_2\text{O} \rightarrow \ldots \text{q} \ldots + 3 \text{NaH}_2\text{PO}_2 \]

1. **Identify the reactants**:
- White phosphorus (\( \text{P}_4 \))
- Sodium hydroxide (\( \text{NaOH} \))
- Water (\( \text{H}_2\text{O} \))

2. **Determine the products**:
- When white phosphorus reacts with sodium hydroxide and water, it produces phosphine (\( \text{PH}_3 \)) and sodium hypophosphite (\( \text{NaH}_2\text{PO}_2 \)).

3. **Fill in the blank**:
- Therefore, \( \text{q} = \text{PH}_3 \).

### Step 3: Analyze the third reaction
The third reaction given is:
\[ \text{PH}_4\text{I} + \text{KOH} \rightarrow \text{KI} + \text{H}_2\text{O} + \ldots \text{r} \ldots \]

1. **Identify the reactants**:
- Phosphonium iodide (\( \text{PH}_4\text{I} \))
- Potassium hydroxide (\( \text{KOH} \))

2. **Determine the products**:
- The reaction of phosphonium iodide with potassium hydroxide produces potassium iodide (\( \text{KI} \)), water (\( \text{H}_2\text{O} \)), and phosphine (\( \text{PH}_3 \)).

3. **Fill in the blank**:
- Therefore, \( \text{r} = \text{PH}_3 \).

### Final Answers
- \( \text{p} = \text{PH}_3 \)
- \( \text{q} = \text{PH}_3 \)
- \( \text{r} = \text{PH}_3 \)

Thus, the complete filled reactions are:
1. \( \text{Ca}_3\text{P}_2 + 6 \text{HCl} \rightarrow 3 \text{CaCl}_2 + \text{PH}_3 \)
2. \( \text{P}_4 + 3 \text{NaOH} + 3 \text{H}_2\text{O} \rightarrow \text{PH}_3 + 3 \text{NaH}_2\text{PO}_2 \)
3. \( \text{PH}_4\text{I} + \text{KOH} \rightarrow \text{KI} + \text{H}_2\text{O} + \text{PH}_3 \)